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5n^2-50n+105=0
a = 5; b = -50; c = +105;
Δ = b2-4ac
Δ = -502-4·5·105
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-20}{2*5}=\frac{30}{10} =3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+20}{2*5}=\frac{70}{10} =7 $
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